Answer :
The heat required by the cube of iron has been 602.64 J.
The specific heat has been given as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.
The heat required has been expressed as:
[tex]\rm Heat=mass\;\times\;specific\;heat\;\times\;\Delta \textit T[/tex]
Computation for the heat required by Iron sample
The mass of the sample has been given as 55.8 g
The specific heat of tin has been, [tex]c_p=0.450\;\rm J/g^\circ C[/tex]
The change in temperature, ([tex]\Delta T[/tex]) has been:
[tex]\Delta T=\text{Final temperature-Initial temperature}\\\Delta T=49^\circ \text C-25^\circ \text C\\\Delta T=24^\circ \text C[/tex]
Substituting the values for the heat required:
[tex]\rm Heat=55.8\;g\;\times\;0.450\;J/g^\circ C\;\times\;24^\circ C\\Heat=602.64\;J[/tex]
The heat required by the cube of iron has been 602.64 J.
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