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Lora (of mass 54 kg) is an expert skier. She
starts at 2.6 m/s at the top of the lynx run,
which is 51 m above the bottom.
What is her final kinetic energy at the bottom of the ski run?

Lora (of mass 54 kg) is an expert skier. She starts at 2.6 m/s at the top of the lynx run, which is 51 m above the bottom. What is her final kinetic energy at t class=

Answer :

The mechanical energy at top =Mechanical energy at bottom

  • Mass=m=54kg
  • Height=h=51m
  • Acceleration due to gravity=g=10m/s^2
  • Velocity=v=2.6m/s

[tex]\\ \tt\longmapsto M_{initial}=M_{Final}[/tex]

  • Final energy at bottom=The kinetic energy

[tex]\\ \tt\longmapsto KE=M_{initial}[/tex]

[tex]\\ \tt\longmapsto KE=P.E_{(Top)}+K.E_{(Top)}[/tex]

[tex]\\ \tt\longmapsto K.E=mgh+\dfrac{1}{2}mv^2[/tex]

[tex]\\ \tt\longmapsto K.E=m\left(gh+\dfrac{v^2}{2}\right)[/tex]

[tex]\\ \tt\longmapsto K.E=54\left((10)(51)+\dfrac{2.6^2}{2}\right)[/tex]

[tex]\\ \tt\longmapsto K.E=54\left(510+\dfrac{6.76}{2}\right)[/tex]

[tex]\\ \tt\longmapsto K .E=54(510+3.38)[/tex]

[tex]\\ \tt\longmapsto K.E=54(513.38)[/tex]

[tex]\\ \tt\longmapsto K.E=27722.52J[/tex]

[tex]\\ \tt\longmapsto K.E=27.7KJ[/tex]

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