Answer :
1) balanced chemical equation.
[tex]4\ Fe_{(s)}\ +\ 3\ O_{2}_{(g)}\ ->\ 2\ Fe_{2}O_{3}_{(s)}[/tex]
2) solve.
[tex]=0.20\ mol\ Fe[/tex] × [tex]\frac{2\ mol\ Fe_{2}O_{3}}{4\ mol\ Fe}[/tex]
= 0.10 mol Fe₂O₃
1) balanced chemical equation.
[tex]4\ Fe_{(s)}\ +\ 3\ O_{2}_{(g)}\ ->\ 2\ Fe_{2}O_{3}_{(s)}[/tex]
2) solve.
[tex]=0.20\ mol\ Fe[/tex] × [tex]\frac{2\ mol\ Fe_{2}O_{3}}{4\ mol\ Fe}[/tex]
= 0.10 mol Fe₂O₃