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Order the angle measures , , and from least to greatest.
(Note that the figure is not drawn to scale.)

Order the angle measures , , and from least to greatest. (Note that the figure is not drawn to scale.) class=

Answer :

Mark the theorem below

  • The angle which measures biggest the opposite side of that angle is biggest.

Here

  • 8<10<12
  • JH<IH<JI

Now

  • <I < <J < <H

Answer:

least to greatest: ∠I < ∠J < ∠H

Explanation:

angle I:

cosI = [tex]\frac{10^2+12^2-8^2}{2*10*12}[/tex]

I = [tex]cos^{-1} (\frac{3}{4} )[/tex]

I = 41.41°

angle H:

cosH = [tex]\frac{10^2+8^2-12^2}{2*10*8}[/tex]

H = [tex]cos^{-1} (\frac{1}{8} )[/tex]

H = 82.82°

angle J:

cosJ = [tex]\frac{8^2+12^2-10^2}{2*8*12}[/tex]

J = [tex]cos^{-1}(\frac{9}{16} )[/tex]

J = 55.77°

They sum up to 180°, so the steps are correct.

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