Answer:
The current is 0.548 Amperes
Explanation:
That is; Rt = R₁ +R₂ +R₃ + ...........+ Rn
[tex]\frac{1}{Rt} =\frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} + .....+\frac{1}{Rn}[/tex]
Step 1: Effective resistance for resistors in parallel
[tex]\frac{1}{Rt} =\frac{1}{R1} +\frac{1}{R2}[/tex]
[tex]\frac{1}{Rt} =\frac{1}{6} +\frac{1}{8}[/tex]
[tex]\frac{1}{Rt} =\frac{7}{24}[/tex]
[tex]Rt=3.43 ohms[/tex]
Step 2: Total resistance for the circuit
Resistors 3.43 ohms and 13 ohms are in series
For resistors in series.
Rt = R₁ +R₂
Thus, effective resistance = 3.43 ohms + 13 ohms
= 16.43 ohms
The total resistance for the circuit is 16.43 ohms
step 3: Current in the circuit
Total resistance = 16.43 ohms
Voltage = 9.0 volts
But; from the Ohm's law, I =V/R
Thus, current, [tex]I = \frac{9}{16.43} \\= 0.548 Amperes[/tex]
Answer:
The current will be 0,54 amperes
Explanation:
The circuit has the appearance from the scheme.
6 Ω and 8 Ω are the resistances in parallel, so to calculate the equivalent resistance we have to add the inverses of each one and then raise it to -1
(Req)*-1 = 1/6 + 1/8 = 24/7 Ω
24/7 Ω + 13 Ω (both are in series, we have to sum each other) = 115/7 Ω
THIS IS THE TOTAL RESISTANCE.
Now we can apply The Ohm's law.
ΔV = i . R
9 V / 115/7 Ω = 0.54 Amperes
