Margin of error = 0.8226401
Confidence interval = (9.17736,10.82264)
We have given data for one week recorded for 6 plants.
With a sample standard deviation of 1 inch and a sample mean of 10 inches.
For this sample, it is given that,
Sample size = n = 6
Sample SD = s = 1
Sample mean = x = 10
At a 0.10 significance level, the critical point is with t-distribution (n-1)df=5 df,
t* =2.015048
Margin of error = E=2.015048*s/ √n = 0.8226401
Confidence interval
= (9.17736,10.82264)
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