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A stone is thrown vertically upwards from the ground with a velocity of 49m/s. after 2 seconds, another stone is thrown vertically upwards from the same place on the ground. If the two stones strike the ground at the same time, find the velocity with which the second stone was thrown upwards.​

Answer :

Answer:

39.2 m/s

Explanation:

Find the time for the first one to hit the ground

h = vo t - 4.9 t^2     with h = o

0 = 49 t - 4.9 t^2       t = 10

second stone hits ground in 10 - 2 - 8 seconds

0 = vo (8) - 4.9(8)^2

vo = 39.2 m/s

   

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