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Balance the nuclear reaction equation for the beta minus decay of iodine-131 by completing the missing numbers. superscript 131 subscript 53 upper i right arrow superscript question mark subscript 54 upper x e plus superscript 0 subscript question mark e. the superscript of xenon is . the subscript of the electron is .

Answer :

pstnonsonjoku

Beta minus decay has to do with the loss of an electron.  The superscript on the daughter nucleus is 131 while the subscript  is 54;

What is a beta minus decay?

The term beta minus decay has to do with the loss of an electron. The daughter nucleus so formed is always going to have an atomic number that is greater than that of the parent by 1 unit.

The complete nuclear reaction here is; [tex]\frac{131}{53} I ------- > \frac{131}{54} Xe + \frac{0}{-1} e[/tex] . The  daughter nucleus here is Xe while the parent nucleus is I.

Learn more about beta decay: https://brainly.com/question/25455333

kdavis35

Answer:

The superscript of xenon is 131

The subscript of the electron is -1

Step-by-step explanation:

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