Answer :
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Solve the equation:
[tex]\mathsf{\ell og_5(3x+1)=2}\\\\\\ \mathsf{3x+1=5^2}\\\\ \mathsf{3x+1=25}\\\\ \mathsf{3x=25-1}\\\\ \mathsf{3x=24}\\\\ \mathsf{x=\dfrac{24}{3}}\\\\\\ \mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the answer.} [/tex]
Solution set: S = {8}.
I hope this helps. =)
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Solve the equation:
[tex]\mathsf{\ell og_5(3x+1)=2}\\\\\\ \mathsf{3x+1=5^2}\\\\ \mathsf{3x+1=25}\\\\ \mathsf{3x=25-1}\\\\ \mathsf{3x=24}\\\\ \mathsf{x=\dfrac{24}{3}}\\\\\\ \mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the answer.} [/tex]
Solution set: S = {8}.
I hope this helps. =)