Answered

A baseball player holds a 1.42 N baseball in his hand, a distance of 34.0 cm from the elbow joint as shown in the figure below. The biceps attached at a distance of 2.75 cm from the elbow exerts an upward force of 12.6 N on the forearm. Consider the forearm and hand to be a uniform rod with a mass of 1.20 kg. Calculate the net torque acting on the forearm and hand.

Answer :

Pyrexien0

Answer:

90.3N

Explanation:

⊥mg = (0.170 m)(1.20 kg) 9.81 m/s

τ ball = r⊥Wball = (0.340 m)(1.42 N) = − 0.483 N ⋅m

F − 2.001− 0.483 N ⋅m = 0

F = 2.484 N ⋅m

0.0275 m = 90.3 N

khuranashilpa76

The net torque acting on the forearm and hand is 90.3N

What is torque?

Torque is a measure of the pressure that can motivate an object to rotate about an axis. simply as pressure is what causes an object to accelerate in linear kinematics, torque is what reasons an item to collect angular acceleration. Torque is a vector amount.

⇒mg = (0.170 m)(1.20 kg) 9.81 m/s

⇒torque = r⊥weight of the ball

⇒ (0.340 m)(1.42 N) = − 0.483 N ⋅m

⇒F = − 2.001− 0.483 N ⋅m = 0

⇒F = 2.484 N ⋅m

⇒0.0275 m = 90.3 N

Learn more about Force here:-

#SPJ2

Other Questions