Answer :
The theoretical weight of sodium borohydride is 1900 g
What is the weight of sodium borohydride needed?
Now we know that the theoretical weight is the weight that is obtained from the stoichiometry of the reaction. Now we are given that the number of moles of the benzil is 50 moles and the reaction is 1:1.
1 mole of benzil reacts with 1 mole of sodium borohydride
50 moles of benzil reacts with 50 moles of sodium borohydride
Thus;
Mass of sodium borohydride = 50 moles * 38 g/mol
= 1900 g of sodium borohydride
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