Answer :
from x=a to x=b, with n subintervls, the width between each is (b-a)/n
so from x=3 to x=5 and 4 intervales is (5-3)/4=2/4=1/2
increments of 1/2 each time
we need 4 of them
I see that xi is the right endpoint so I would guess that we take the right Riemann sum
so we start at 3+0.5 or 3.5
so 3.5, 4,4.5,5
C I would say
so from x=3 to x=5 and 4 intervales is (5-3)/4=2/4=1/2
increments of 1/2 each time
we need 4 of them
I see that xi is the right endpoint so I would guess that we take the right Riemann sum
so we start at 3+0.5 or 3.5
so 3.5, 4,4.5,5
C I would say