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a monolayer containing 3.18×10-6 g of oleic acid has an area of 20.0 cm2. the density of oleic acid is 0.895 g / ml. what is the thickness of the monolayer (the length of an oleic acid molecule)? 5.69×10-5 cm 1.42×10-7 cm 7.11×10-5 cm 5.63×10-6 cm 1.78×10-7 cm

Answer :

a monolayer containing 3.18×10-6 g of oleic acid has an area of 20.0 cm2. the density of oleic acid is 0.895 g / ml 1.78×10-7 cm is the thickness of the monolayer

Here given data is monolayer containing 3.18×10-6 g of oleic acid has an area of 20.0 cm2 and the given density of oleic acid is 0.895 g / ml and we have to find thickness of the monolayer=?

So from the information provided we have to calculate volume of monolayer hence, the thickness

Therefore volume=area × height

So given density = mass/volume

0.895 g / ml=3.18×10-6 g × x ml

X ml = 3.18×10-6 g / 0.895 g / ml = 0.35×10⁻⁵cm2

Volume of monolayer, volume = area × thickness so thickness = volume/area

0.35×10⁻⁵cm2 / 20.0 cm2 = 1.78×10-7 cm

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