Solution:
The statement is given below as
[tex]\Delta ABC\cong\Delta DCB[/tex]From the image in the question, we can see that
[tex]\begin{gathered} \angle BAC\cong BDC \\ \angle ACB\cong CBD \\ They\text{ share a common side} \\ BC \end{gathered}[/tex]Concept:
If two angles and a nonincluded side of one triangle are congruent to two angles and a nonincluded side of a second triangle, then the triangles are congruent.
Hence,
With the statements above, the final answer is
[tex]\Rightarrow AAS[/tex]OPTION B is the right answer