Answer :

[tex]\begin{gathered} 8P3=336 \\ Let: \\ A=A_{\text{ }}senior_{\text{ }}is__{\text{ }}top_{\text{ }}3 \\ P(A\cap A_{-1}\cap A_{-2})=\frac{8}{14}\cdot\frac{7}{13}\cdot\frac{6}{12}=0.1538 \end{gathered}[/tex]

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