The two angles shown are supplementary.162°Which equation can be solved to find the value of x, and what is the value of x?A.162° + Xo = 90°; x = 72B.162° + x° = 180°; x = 18C.162° + x = 360°; x= 198D.162° + x = 180°; x = 242

Supplementary angles are two angles whose sum is exactly 180, therefore:
162 + x = 180
Solving for x:
subtract 162 from both sides:
x = 180 - 162
x = 18