Please help with this question.n1 = 1, n2 = 1.32, theta1 = 35°, theta2 = ?

In order to calculate the angle of the refracted light, we can use the law of refraction below:
[tex]n_1\sin\theta_1=n_2\sin\theta_2[/tex]So, using the given information, we have:
[tex]\begin{gathered} 1\sin35°=1.32\sin\theta_2\\ \\ 0.5736=1.32\sin\theta_2\\ \\ \sin\theta_2=\frac{0.5736}{1.32}\\ \\ \sin\theta_2=0.4345\\ \\ \theta_2=25.75° \end{gathered}[/tex]Therefore the angle of the refracted light is 25.75°.