Answer:
[tex]\begin{gathered} \text{Amplitude}=3 \\ \text{Midline is at: }y=1 \\ \text{Period}=\pi \end{gathered}[/tex]we can now graph the function as;
Explanation:
Given the equation;
[tex]f(x)=3\sin (2x)+1[/tex]Firstly, to derive the period, Amphitude and midline, let us compare to the general form;
[tex]\begin{gathered} f(x)=A\sin (Bx+C)+D \\ A=\text{Amplitude} \\ D=\text{midline} \\ \text{ since C=0 for the given equation;} \\ \text{Period=}\frac{2\pi}{B} \end{gathered}[/tex]From the given equation;
[tex]\begin{gathered} A=3 \\ D=1 \\ B=2 \\ \therefore \\ \text{Amplitude}=3 \\ \text{Midline is at: }y=1 \\ \text{Period}=\frac{2\pi}{2} \\ \text{Period}=\pi \end{gathered}[/tex]With the above characteristics we can now graph the function as;
