Answer :
We will use the next rule
[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}}[/tex]Then
[tex]\sqrt[7]{x^6}\ast\sqrt[5]{x}=x^{\frac{6}{7}}\ast x^{\frac{1}{5}}=x^{\frac{6}{7}+\frac{1}{5}}[/tex][tex]x^{37/35}[/tex]
We will use the next rule
[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}}[/tex]Then
[tex]\sqrt[7]{x^6}\ast\sqrt[5]{x}=x^{\frac{6}{7}}\ast x^{\frac{1}{5}}=x^{\frac{6}{7}+\frac{1}{5}}[/tex][tex]x^{37/35}[/tex]