Answer :
Given
The Scranton community gym is 90 feet long 60 feet wide and 40 feet high.
volume of a regulated basketball is approximately 410 cubic inches
Find
Give a lower and upper bound for the number of basketballs it would take to fill the gym
Explanation
Volume of gym =
[tex]90\times60\times40=21600\text{ }cubic\text{ }ft[/tex]1 ft = 12 inch
so ,
21600 cubic ft =
[tex]\begin{gathered} 21600\times(12)^3 \\ 373,248,000\text{ }cubic\text{ }inches \end{gathered}[/tex]therefore ,
number of basketballs it would take to fill the gym =
[tex]\begin{gathered} 373,248,000\div410 \\ 910,360.96 \end{gathered}[/tex]so , it is in the bound of 900,000 - 1,000,000
Final Answer
Hence , a lower and upper bound for the number of basketballs it would take to fill the gym is 900,000 - 1,000,000