The rectangle is given by:
The area of this rectangle is given by:
[tex]\begin{gathered} A=w\cdot h \\ \end{gathered}[/tex]Where:
[tex]\begin{gathered} w=\sqrt[]{(3-(-1))^2+(1-(-3))^2} \\ w=4\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} h=\sqrt[]{(-1-(-3))^2+(-3-(-1))^2} \\ h=2\sqrt[]{2} \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} A=4\sqrt[]{2}\cdot2\sqrt[]{2} \\ A=16 \end{gathered}[/tex]Answer:
16 units²
