I need help with the one that is talking about a horizontal force of 89.7 NShown in the picture below

According to Newton's Second Law of Motion, the net force acting over an object is responsible for the acceleration of the object:
[tex]\Sigma F=ma[/tex]Since the friction and the horizontal force act in opposite directions, then:
[tex]\Sigma F=F_H-f[/tex]Where F_H represents the horizontal force and f represents the friction.
Replace the expression for the net force and isolate f:
[tex]\begin{gathered} F_H-f=ma \\ \Rightarrow f=F_H-ma \end{gathered}[/tex]To find the magnitude of the friction, replace F_H=89.7N, m=22.5kg and a=1.23m/s^2:
[tex]\begin{gathered} \Rightarrow f=(89.7N)-(22.5\operatorname{kg})(1.23\frac{m}{s^2}) \\ =89.7N-27.675N \\ =62.025N \\ \approx62.0N \end{gathered}[/tex]Therefore, the magnitude of the force of kinetic friction acting on the crate is 62.0 N.