Answer :
When you have two proportional figures (in this case the building and their windows) you have that:
Then, you have:
[tex]\frac{11in}{x}=\frac{1.5ft}{108ft}[/tex]You solve the x:
[tex]\begin{gathered} (108ft)11in=1.5ft(x) \\ 1188ft\cdot in=1.5ft\cdot x \\ \frac{1188ft\cdot in}{1.5ft}=x \\ 792in=x \end{gathered}[/tex]You change the inches to feet: (1 ft is equal to 12 inches)
[tex]792in\cdot\frac{1ft}{12in}=66ft[/tex]Then, the width of the building is 66 feet.
