[tex]\begin{gathered} 4x-5<19 \\ 4x<19+5 \\ 4x<24 \\ x<\frac{24}{4} \\ x<6 \end{gathered}[/tex][tex]\begin{gathered} 2x-2<4 \\ 2x<4+2 \\ 2x<6 \\ x<\frac{6}{2} \\ x<3 \end{gathered}[/tex]
Hence, the solution in interval notation is given by:
[tex](-\infty,3)\cup(-\infty,6)=(-\infty,6)[/tex]
