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The circle below is centered at the origin and has a radius of 5. What is itsequation?OAX2²-2²=5OB.X²-2²=25OC. x² +2²=51OD. x² + y² = 25

The circle below is centered at the origin and has a radius of 5. What is itsequation?OAX2²-2²=5OB.X²-2²=25OC. x² +2²=51OD. x² + y² = 25 class=

Answer :

The equation of a circle centered at the origin is given to be:

[tex]x^2+y^2=r^2[/tex]

where r is the radius of the circle.

The radius of the circle in the question is given to be 5 units.

Therefore, the equation of the circle will be:

[tex]\begin{gathered} x^2+y^2=5^2 \\ \therefore \\ x^2+y^2=25 \end{gathered}[/tex]

OPTION D is correct.

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