Answer :

Answer:

275 historic buildings

Explanations:

The given concept will form an arithmetic sequence

Given the following parameters:

First-term "a" = 5

Number of terms "n" = 2003 - 1993

Number of terms "n" = 10

common difference = 5

Determine the sum of terms for the whole period

[tex]\begin{gathered} S_{10}=\frac{n}{2}(2a+(n-1)d) \\ S_{10}=\frac{10}{2}\lbrack2(5)+(10-1)\cdot5\rbrack \\ S_{10}=\frac{10}{2}\lbrack10+9(5)\rbrack \\ S_{10}=5\lbrack10+45\rbrack \\ S_{10}=5(55) \\ S_{10}=275historic\text{ building} \end{gathered}[/tex]

Hence by the end of 2003, 275 historic buildings would be lost

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