To find the surface area of the square pyramid, we will use the formula below:
[tex]\text{Surface area =A+}\frac{1}{2}PS[/tex]where A is the area of the base
P is the perimeter
S is the slant height
From the question,
s= 6cm
l =4cm
Area of the base= l x l = 4 x 4 = 16 cm²
[tex]\frac{1}{2}ps=\frac{1}{2}\times4\times4\times6=48\operatorname{cm}[/tex][tex]\text{Surface area = 16+48=64cm}^2[/tex]