What is the intensity of a sound wave if the power output of the source is 3.56 W and the surface area is 1.58 m²?0.444 W/m²5.62 W/m²2.25 W/m²1.98 W/m²

Answer :

Given:

The power output of the source is

[tex]P=3.56\text{ W}[/tex]

The surface area is,

[tex]A=\text{ 1.58 m}^2[/tex]

Required: intensity of the sound wave

Explanation:

The intensity of the sound wave can be found by the formula.

that is given by,

[tex]I=\frac{P}{A}[/tex]

here, P is the power output of the source and A is the surface area.

Plugging all the values in the above formula, we get:

[tex]\begin{gathered} I=\frac{3.56\text{ W}}{1.58\text{ m}^2} \\ I=2.25\text{ w/m}^2 \end{gathered}[/tex]

Result: Thus, the intensity of the sound wave is

[tex]2.25\text{ w/m}^2[/tex]

and the option 3rd is correct.

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