Answer :
This is an arithmetic sequence, with common difference of 4, a = 1.
[tex] a_{n} [/tex] = a₁ + (n - 1)d
205 = 1 + (n - 1)4
204 = 4n - 4
208 = 4n
n = 52
So, yes. It is the 52nd term in the sequence.
[tex] a_{n} [/tex] = a₁ + (n - 1)d
205 = 1 + (n - 1)4
204 = 4n - 4
208 = 4n
n = 52
So, yes. It is the 52nd term in the sequence.