Answer :
hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)
d ⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
the line is perpendicular to the plane .
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)
d ⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
the line is perpendicular to the plane .