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Which statement and explanation about the product of a 3-digit number and a 2-digit number is correct?

A. The product always has 4 digits. The least 3-digit number is 100, and the least 2-digit number is 10. The product of 100 and 10 has 4 digits, so any product of a 3-digit and a 2-digit number must have 4 digits.
B. The greatest number of digits in the product is 6. The greatest 3-digit number is 999, and the greatest 2-digit number is 99. The product of 3 digits and 2 digits equals 6 digits, so no product of a 3-digit and a 2-digit number can have more digits.
C. The product always has 5 digits. The greatest 3-digit number is 999, and the greatest 2-digit number is 99. The product of 999 and 99 has 5 digits, so any product of a 3-digit and a 2-digit number must have 5 digits.
D. The greatest number of digits in the product is 5. The greatest 3-digit number is 999, and the greatest 2-digit number is 99. The product of 999 and 99 has 5 digits, so no product of a 3-digit and a 2-digit number can have more digits.

Answer :

Its D- 999*99 is a 5 digit #, but 100*10 is a 4 digit- 1000- so it can be less.
MrRoyal

The correct statement is :

D. The greatest number of digits in the product is 5. The greatest 3-digit number is 999, and the greatest 2-digit number is 99. The product of 999 and 99 has 5 digits, so no product of a 3-digit and a 2-digit number can have more digits.

The smallest 2 digits is 10, and the smallest 3 digits is 100

Their product is:

[tex]10 \times 100 = 1000[/tex] i.e. 4 digits

The greatest 2 digits is 99, and the greatest 3 digits is 999

Their product is:

[tex]99 \times 999 = 98901[/tex]  i.e. 5 digits

This means that;

No product of the digits can have more than 5 digits

And, no product can have less than 4 digits

Hence, (d) is correct

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https://brainly.com/question/16032803

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