we know that
The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.
so
[tex]Angle\ XYZ=\frac{1}{2}[arc\ UW+arc\ XZ][/tex]
In this problem we have
[tex]arc\ UW=110\°[/tex]
[tex]arc\ XZ=42\°[/tex]
substitute the values
[tex]Angle\ XYZ=\frac{1}{2}[110\°+42\°][/tex]
therefore
the answer is the option B
[tex]\frac{1}{2}[110\°+42\°][/tex]
