Answer :
The idea here is to use both equations to solve for “a” using the provided “y” value. In this case we can use the y=1.3 to solve for “x” in the second equation (yâ’1.2) = -1.2(x-0.5). Then, we can plug-in the value for “x” from the second equation into the first equation a(0.3â’y) + 1.1 + 2.4x = 0. The answer for “a” is 21/10=2.1.