Answer:
Rate of increase in water pressure is [tex]992\ \dfrac{\text{atm}}{\text{km}}[/tex]
Step-by-step explanation:
The water pressure on Mustafa as he dives is increasing at a rate of [tex]0.992\ \dfrac{\text{atm}}{\text{m}}[/tex]
We know that,
[tex]1\ Kilometer=1\ meter\ \ \ \Rightarrow \ \ \ 1\ meter=10^{-3}\ Kilometer[/tex]
Hence,
[tex]0.992\ \dfrac{\text{atm}}{10^{-3}\ \text{km}}=0.992\times 10^3\ \dfrac{\text{atm}}{\text{km}}=992\ \dfrac{\text{atm}}{\text{km}}[/tex]
Therefore, rate of increase in water pressure is [tex]992\ \dfrac{\text{atm}}{\text{km}}[/tex]
