Answer :
The
correct answer is in file attached
we have
triangle RST
m∠R = 60, m∠S = 80 and m∠T=180-(80+60)=40
RS=4
triangle EFD
m∠F = 60, m∠D = 40 and m∠E=180-(60+40)=80
EF=4
Therefore
The triangles RST and EFD are congruents because they have two angles and the side common to them, respectively, equal.
This is the theorem of ASA (angle-side-angle).
Explication
Side common--------> RS=EF
Angles RS------------- > m∠R = 60 m∠S = 80
Angles EF------------- > m∠E = 80 m∠F = 60
The segment which is congruent to RT is FD, because angles of RT are 60 and 40, and angles of FD also are 60 and 40.
we have
triangle RST
m∠R = 60, m∠S = 80 and m∠T=180-(80+60)=40
RS=4
triangle EFD
m∠F = 60, m∠D = 40 and m∠E=180-(60+40)=80
EF=4
Therefore
The triangles RST and EFD are congruents because they have two angles and the side common to them, respectively, equal.
This is the theorem of ASA (angle-side-angle).
Explication
Side common--------> RS=EF
Angles RS------------- > m∠R = 60 m∠S = 80
Angles EF------------- > m∠E = 80 m∠F = 60
The segment which is congruent to RT is FD, because angles of RT are 60 and 40, and angles of FD also are 60 and 40.

Similar triangles, may or may not be congruent.
The triangles are congruent by ASA
The given parameters are:
[tex]\mathbf{\triangle RST}[/tex]
[tex]\mathbf{\angle R = 60}[/tex]
[tex]\mathbf{\angle S = 80}[/tex]
[tex]\mathbf{RS = 4}[/tex]
[tex]\mathbf{\triangle EFD}[/tex]
[tex]\mathbf{\angle F = 60}[/tex]
[tex]\mathbf{\angle D = 40}[/tex]
[tex]\mathbf{EF = 4}[/tex]
The third angles of both triangles are:
[tex]\mathbf{\angle T = 180 - 60 - 80}[/tex]
[tex]\mathbf{\angle T = 40}[/tex]
[tex]\mathbf{\angle E = 180 - 60 -40}[/tex]
[tex]\mathbf{\angle E = 100}[/tex]
The above highlights mean that:
- The triangles have two congruent angles
- The triangles have one congruent side
This means that, the triangles are congruent by ASA
And the congruent sides are:
[tex]\mathb{RS = EF}[/tex]
Read more about congruent triangles at:
https://brainly.com/question/18799165