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The sum of the numerator and the denominator of the certain fraction is equal to 4,140. When the fraction was reduced, the result was 7/13. What was the original fraction?

Answer :

WojtekR
Original fraction was [tex]\dfrac{7\cdot k}{13\cdot k}[/tex] where [tex]k[/tex] is a reduced common factor. We know that:

[tex]7k+13k=4140\\\\20k=4140\qquad|:20\\\\\boxed{k=207}[/tex]

so original fraction:

[tex]\dfrac{7\cdot k}{13\cdot k}=\dfrac{7\cdot 207}{13\cdot 207}=\boxed{\dfrac{1449}{2691}}[/tex]

A function assigns the values. The original function is 1449/2691.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Given that when the fraction was reduced, the result was 7/13. Therefore, if it is assumed that the fraction was reduced by a. Therefore, we can write the original function as,

(7×a)/(13×a)

Now, since the sum of the numerator and the denominator is 4140. Therefore,

(7×a) + (13×a) = 4140

7a + 13a = 4140

20a = 4140

a = 207

Now, the value of the original function is

(7×a)/(13×a)

= (7×207) / (13×207)

= 1449 / 2691

Hence, the original function is 1449/2691.

Learn more about Function:

https://brainly.com/question/5245372

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