Answer :
[tex]\bf \textit{area of a trapezoid}\\\\
A=\cfrac{h(a+b)}{2}~~
\begin{cases}
a,b=\stackrel{bases}{parallel~sides}\\
h=height\\
---------\\
a=9.2\\
b=7.7\\
h=6.8
\end{cases}\implies A=\cfrac{6.8(9.2+7.7)}{2}[/tex]
Answer:
The area of a trapezoid is 57.46 cm².
Step-by-step explanation:
Formula
[tex]Area\ of\ trapezoid = \frac{(a + b)}{2}\times h[/tex]
Where a, b are the two parallel bases of the trapezoid.
h is the height of the trapezoid.
As given
Trapezoid with bases that measure 9.2 cm and 7.7 cm and height 6.8 cm.
Put in the formula
[tex]Area\ of\ trapezoid = \frac{(9.2 + 7.7)}{2}\times 6.8[/tex]
[tex]Area\ of\ trapezoid = \frac{16.9}{2}\times 6.8[/tex]
[tex]Area\ of\ trapezoid = 8.45\times 6.8[/tex]
Area of trapezoid = 57.46 cm²
Therefore the area of a trapezoid is 57.46 cm².