Answer :
let
x-------> the cost of the burger
y-------> the cost of the sandwiches
we know that
3x+2y=27-----> equation 1
2x+y=27-11-----> 2x+y=16-----> multiply by -2-----> -4x-2y=-32--> equation 2
adds equation 1 and equation 2
3x+2y=27
-4x-2y=-32
----------------
-x=27-32-----> x=5
3*5+2y=27----> 2y=27-15-----> y=6
therefore
the answer is the option
3) The student's conclusion is correct because the solution to the system of equations 3x + 2y = 27 and 2x + y = 16 is (5, 6).
x-------> the cost of the burger
y-------> the cost of the sandwiches
we know that
3x+2y=27-----> equation 1
2x+y=27-11-----> 2x+y=16-----> multiply by -2-----> -4x-2y=-32--> equation 2
adds equation 1 and equation 2
3x+2y=27
-4x-2y=-32
----------------
-x=27-32-----> x=5
3*5+2y=27----> 2y=27-15-----> y=6
therefore
the answer is the option
3) The student's conclusion is correct because the solution to the system of equations 3x + 2y = 27 and 2x + y = 16 is (5, 6).