Answer :
The mass of CO2 produced is calculated as follows
write the equation for decomposition of NaHCO3
2NaHCO3 -----> Na2CO3 +CO2 + H20
find the moles of NaHCO3 = mass/molar mass = 40g/ 84 g/mol= 0.476 mole
by use of reacting ratio between NaHCO3 to CO2 which is 2:1 the moles of CO2 = 0.476 /2 = 0.238 moles
mass of CO2 = moles x molar mass
that is = 0.238 moles x 44 g/mol=10.472 g
write the equation for decomposition of NaHCO3
2NaHCO3 -----> Na2CO3 +CO2 + H20
find the moles of NaHCO3 = mass/molar mass = 40g/ 84 g/mol= 0.476 mole
by use of reacting ratio between NaHCO3 to CO2 which is 2:1 the moles of CO2 = 0.476 /2 = 0.238 moles
mass of CO2 = moles x molar mass
that is = 0.238 moles x 44 g/mol=10.472 g