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The expression 2(l + w) is used to calculate the perimeter of a rectangle, where l is length and w is width. If the length is Fraction 2 over 5 unit and the width is Fraction 1 over 5 unit, what is the perimeter of the rectangle in units?

Fraction 3 over 5 unit
1 unit
1Fraction 1 over 5 units
2Fraction 3 over 5 units

The expression 2(l + w) is used to calculate the perimeter of a rectangle, where l is length and w is width. If the length is Fraction 2 over 5 unit and the wid class=

Answer :

israrahman03
So basically, since the formula is 2(l × w), we will do:
(Length) 2/5 + 2/5 (the same thing as multiplying it by two) which equals 4/5.
Then we do the same for the width:
(Width) 1/5 + 1/5 (also the same thing as multiplying by two) to get 2/5.

Now we just add both fractions: 4/5 + 2/5 = 1 1/5 
So the answer is C. 

The perimeter of the rectangle is 6/5.

Given that

The expression 2(l + w) is used to calculate the perimeter of a rectangle, Where l is length and w is width.

If the length is Fraction 2 over 5 units and the width is Fraction 1 over 5 units,

We have to determine

What is the perimeter of the rectangle in units?

According to the question

The expression 2(l + w) is used to calculate the perimeter of a rectangle, Where l is length and w is width.

[tex]\rm Perimeter = 2(l+w)\\ [/tex]

The length is 2/5 and the width is 1/5.

Then,

The perimeter of the rectangle is

[tex]\rm Perimeter = 2(l+w)\\\\ \rm Perimeter = 2(\dfrac{2}{5}+\dfrac{1}{5})\\\\ Perimeter = 2(\dfrac{2+1}{5})\\ \\ Perimeter = 2 \times \dfrac{3}{5}\\ \\ Perimeter = \dfrac{6}{5}[/tex]

Hence, The perimeter of the rectangle is 6/5.

To know more about Rectangle click the link given below.

https://brainly.com/question/12895249

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