Answer :
Suppose:
width=x ft
length=(x+10) ft
Area:
x(x+10) ft²
Given that the sides are increased by 10, then the new dimensions will be:
width=(x+10) ft
length=(x+20) ft
thus the area will be:
(x+10)(x+20)=4×(x^2+10x)
solving for x we get:
x=-10 or x=20/3
thus the original width=20/3 and length=(10+20/3)=50/3 ft
width=x ft
length=(x+10) ft
Area:
x(x+10) ft²
Given that the sides are increased by 10, then the new dimensions will be:
width=(x+10) ft
length=(x+20) ft
thus the area will be:
(x+10)(x+20)=4×(x^2+10x)
solving for x we get:
x=-10 or x=20/3
thus the original width=20/3 and length=(10+20/3)=50/3 ft